A. 24
B. 29
C. 42
D. 30
E. None of these
Solution: 30
Explanation: 2, 6, 12, 20 1 x 2, 2 x 3, 3 x 4, 4 x 5, (5 x 6) Answer is 30. Product of two consecutive natural numbers
2) The marked price of a radio is 30% more than its cost price. If a discount of 10% is given on the marked price, find the gain percent.A. 20%
B. 17%
C. 19%
D. 21%
E. None of the above
Solution: B
Explanation:
Given
Let Cost Price = 100 Rs
Marked price = 30 % more than Cost Price
= 30 % of C.P + C.P
= ( ( 30 / 100 ) x 100 ) + 100
= 30 + 100
= 130 Rs
Given Discount = 10 % of marked price
= ( 10 / 100 ) x 130
= 13 Rs
Selling Price = Marked Price - Discount
= 130 - 13
a) 50
b) 100
c) 120
d) 200
Solution: 200
Explanation: Possible ways in which he can attempt 6 questions are
5C4*5C2 = 50
5C3*5C3 = 100
5C2*5C4 = 50
50+100+50 = 200
A. 84
B. 128
C. 120
D. 274
Solution: D
Explanation: Let the two numbers be x and y ,
HCF = 24
LCM = 1344
HCF × LCM = x×y
24×1344 = xy
xy = 32256
(x-y) = 80
x = 80+y
(80+y)×y = 32256
y^2 +80y -32256 = 0
y^2 +224y -144y -32256 = 0
y(y+224) -144(y+224) =0
y = 114 & -224
x = 80+114
x = 194
x+y = 194+80 = 274
A. 9000
B. 10000
C. 9500
D. 10500
Solution: B
Explanation: Given Compound Interest = Rs.2100
Rate of Interest ( r ) = 10 % p.a
No.of years ( n ) = 2
To find , amount received at the beginning => principal
Compound Interest = P [ 1 + ( r / 100 )n- 1 ]
=> 2100 = P[ 1 + ( 10 / 100 )2- 1 ]
=> 2100 = P[ 1 + ( 1 / 10 )2- 1 ]
=> 2100 = P[ ( 11 / 10 )2- 1 ]
=> 2100 = P[ ( 121 / 100 ) - 1 ]
=> 2100 = P[ 21 / 100 ]
=> 2100 x ( 100 / 21 ) = P
Principal = Rs. 10000
Amount invested at the beginning = Rs. 10000
A. 12
B. 1/4
C. 0.155
D. None of these
Solution: B
Explanation:
Let be the 4% of a is 4a/100.
Since this equals 8, we have 4a/100=8.
Solving for a yields a=8×(100/4)=200.
Also, 8% of b equals 8b/100, and this equals 4.
Hence, we have (8/100)×b=4.
Solving for b yields b = 50.
Now, c=b/a=50/200=1/4.
A. 10 days
B. 14 days
C. 15 days
D. 9 days
Solution: C
Amount of work P can do in 1 day = 1/20
Amount of work Q can do in 1 day = 1/30
Amount of work R can do in 1 day = 1/60
P is working alone and every third day Q and R is helping him
Work completed in every three days = 2 × (1/20) + (1/20 + 1/30 + 1/60) = 1/5
So work completed in 15 days = 5 × 1/5 = 1
That is, the work will be done in 15 days
A. 15
B. 10
C. 20
D. 25
Solution: A
Explanation: Manu, Manju and Maya together can do the work = 1/90 + 1/30 + 1/45 = 1+3+2 /90= 1/15 So, They will complete the work in 15 days.
10) Ravi's salary was reduced by 25%. Percentage increase to be effected to bring the salary to the original level isA. 20%
B. 25%
C. 33 1/3%
D. 30%
Solution: C
OFF CAMPUS UPDATES IN TELEGRAMA. Rs. 510
B. Rs. 530
C. Rs. 503
D. Rs. 519
E. None of these
Answer (A)
Explanation
The selling price of the article is, Selling price = Cost Price + Selling price * (Percent
Profit/100)
Selling Price = 480 + (6.25/100)*480 = 510
Hence, the correct option is option A.
A. Rs 935
B. Rs 905
C. Rs 945
D. Rs 975
E. None of these
Answer (C)
Explanation
Let the CP be the Cost Price and SP be Selling Price.
Profit = SP – CP = 996 – CP
Loss = CP -SP = CP – 894
Now as Profit = Loss
2*CP = 1890
CP =945
Hence, the cost price is 945.
a) 9 years
b) 7 years
c) 5 years
d) 3 years
e) None of these
Answer (D)
Explanation
Let the ages of Nishi and Vinnee be x and y.
Now, as per given conditions,
(x/y) = (6/5) i.e 5x=6y
after 9 years,
(x+9)/(y+9) = 9/8 i.e 8x-9y=9
After solving we get x = 18 and y = 15.
Differences in the ages = 18-15=3
Hence, option D is correct.
a) 3478
b) 1418
c) 5673
d) 2147
e)1077
Answer (E)
Explanation
9070 – 15^3 = 5675 , 5675 – 13^3 = 3478 , 3478 – 11^3 = 2147 , 2147 – 9^3 = 1418 ,
1418 –
7^3 = 1075 ≠ 1077 , 1075 – 5^3 = 950
A. Rs. 22 lakh
B. Rs. 18.25 lakh
C. Rs. 18 lakh
D. Rs. 23.25 lakh
E. None of these
Answer (C)
Explanation
The total amount distributed among officers = 45*25000= 11,25,000
If the total amount is x, then this amount is (5/8)x=11,25,000
Hence, x=18,00,000
a) 130
b) 134
c) 132
d) 135
Answer : 132
2. An emergency vehicle travels 10 miles at a speed of 50 miles per hour.How fast must the vehicle travel on the return trip if the round-trip travel time is to be 20 minutes?a) 75 miles per hour
b) 70 miles per hour
c) 65 miles per hour
d) 80 miles per hour
Answer : 75 miles per hour
3. Mary and John can do a piece of work in 24 days; John and Vino in 30 days; Vino and Mary in 40 days. If Mary, John and Vino work together they will complete the work in :a) 10 days
b) 20 days
c) 17 days
d) 15 days
Answer : 20 days.
a) She lost Rs 500.67
b) She lost Rs 666.67
c) She gain Rs 666.67
d) She gain Rs 500.67
Answer : She lost Rs 666.67
5. Find the sum of the first 50 common terms of 12,16,20,... and 18,24,30,....a) 15900
b) 12700
c) 19990
d) 18400
Answer : 15900
6. The time showed by an analog clock at a moment is 11 am then 1234567890 hours later it will show the time as:a)11am
b)11pm
c)5am
d)4pm
Answer : 5am
7. Square of two more than a two digit number is multiplied and divided by 2 and 5 respectively. If twice of the result is equal to 500 then find the number?a) 45
b) 23
c) 87
d) 47
Answer : 23
a) 35 Rs. and 65 paise.
b) 32 Rs. and 63 paise.
c) 30 Rs. and 65 paise.
d) 31 Rs. and 63 paise.
Answer : 31 Rs and 63 paise.
9.A can do a piece of work in 100 days, B and C together can do the same work in 20 days. If B can do the work in same time as that of C and A together then how long C alone can do the same work?a) 100 days
b) 50days
c) 25days
d) 20 days
Answer : 50 days
10. Grass in lawn grows equally thickand in a uniform rate. It akes 24 days for 70 cows and 60 for 30 cows . How many cows can eat away the same in 96 days?a) 18
b) 20
c) 21
d) 19
Answer : 18
11.A lorry starts from Banglore to Mysore at 6.00 A.M,7.00am.8.00 am.....10 pm. Similarly one another starts from Mysore to Banglore at 6.00 am,7.00 am, 8.00 am.....10.00pm. A lorry takes 9 hours to travel from Banglore to Mysore and vice versa.a) 12 lorries and 14 lorries
b) 10 lorries and 14 lorries
c) 14 lorries and 10 lorries
d) 14 lorries and 12 lorries
Answer : 10 lorries and 14 lorries
12.A garrison of 3300 men has provisions for 32 days, when given at a rate of 850 grams per head. At the end of 7 days a reinforcement arrives and it was found that now the provisions will last 8 days less, when given at the rate of 825 grams per head.How, many more men can it feed?a) 1700 men
b) 1800 men
c) 2000 men
d) 2500 men
Answer : 1700 men